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GRE考試技巧數(shù)學(xué)重要考點(diǎn)AP介紹

時(shí)間:2024-07-15 16:21:28 GRE 我要投稿
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GRE考試技巧關(guān)于數(shù)學(xué)重要考點(diǎn)AP介紹

  新GRE考試技巧:數(shù)學(xué)重要考點(diǎn)AP

GRE考試技巧關(guān)于數(shù)學(xué)重要考點(diǎn)AP介紹

  新gre考試實(shí)施以來,不僅對(duì)寫作部分茫然不知所措,就連我們所擅長的數(shù)學(xué)也甚是擔(dān)憂,相信這其中的原因還是由于考生在新gre數(shù)學(xué)復(fù)習(xí)時(shí)沒有把基礎(chǔ)打牢。如果新版gre數(shù)學(xué)基本考點(diǎn)都沒有復(fù)習(xí)到,如何能拿到分?jǐn)?shù)呢?所以說,想要新版gre數(shù)學(xué)考好,復(fù)習(xí)的時(shí)候一定要把基本概念和重要考點(diǎn)都弄扎實(shí)。 天針對(duì)新版gre數(shù)學(xué)復(fù)習(xí),小編給大家整理的是關(guān)于平均數(shù)的相關(guān)內(nèi)容,這些概念在考試中一定會(huì)考到的。希望考生能再接再厲,取得一個(gè)好成績,突破新版gre數(shù)學(xué)難的困境。

  AP

  Average of n numbers of arithmetic progression (AP) is the average of the smallest and the largest number of them. The average of m number can also be written as x + d(m-1)/2.

  Example:

  The average of all integers from 1 to 5 is (1+5)/2=3

  The average of all odd numbers from 3 to 3135 is (3+3135)/2=1569

  The average of all multiples of 7 from 14 to 126 is (14+126)/2=70

  remember:

  Make sure no number is missing in the middle.

  With more numbers, average of an ascending AP increases.

  With more numbers, average of a descending AP decreases.

  AP:numbers from sum

  given the sum s of m numbers of an AP with constant increment d, the numbers in the set can be calculated as follows:

  the first number x = s/m - d(m-1)/2,and the n-th number is s/m + d(2n-m-1)/2.

  Example:

  if the sum of 7 consecutive even numbers is 70, then the first number x = 70/7 - 2(7-1)/2 = 10 - 6 = 4.

  the last number (n=m=7)is 70/7+2(2*7-7-1)/2=10+6=16.the set is the even numbers from 4 to 16.

  Remember:

  given the first number x, it is easy to calculate other numbers using the formula for n-th number: x+(n-1)

  AP:numbers from average

  all m numbers of an AP can be calculated from the average. the first number x = c-d(m-1)/2, and the n-th number is c+d(2n-m-1)/2, where c is the average of m numbers.

  Example:

  if the average of 15 consecutive integers is 20, then the first number x=20-1*(15-1)/2=20-7=13 and the last number (n=m=15) is 20+1*(2*15-15-1)/2=20+7=27.

  if the average of 33 consecutive odd numbers is 67, then the first number x=67-2*(33-1)/2=67-32=35 and the last number (n=m=33) is 67+2*(2*33-33-1)/2=67+32=99.

  Remember:

  sum of the m numbers is c*m,where c is the average.

  由于美國數(shù)學(xué)基礎(chǔ)教育的難度增加導(dǎo)致數(shù)學(xué)考試越來越難,但新gre數(shù)學(xué)復(fù)習(xí)考點(diǎn)都是高中時(shí)候?qū)W到的知識(shí)點(diǎn),考生不要過于緊張,把基本概念弄明白,再記住一些新版gre數(shù)學(xué)必備的詞匯,那么相信新版gre數(shù)學(xué)應(yīng)該沒有問題。

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